Raleigh_Becket
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。。。That's good //@Hermann_Gottlieb: 唔...假如两人加速运动时间T位移就是2T，S=1/2a(2T)²-1/2aT²=3/2aT² 位移差 s=3/2aT²-1/2aT²=aT² 然后我和newt的身高角度θ，手杖初速度是V。施力力度是F，算上空气阻力g常数...我应该能做到打中再弹回来//@Raleigh_Becket: WOW DOC...YOU ARE REALLY GOO 展开全文原微博